Tables, Graphs, Measures of Central Tendency|My homework helper

The incubation rates for the mysterious “O” virus has been recorded in days. The number of days ranges from 5 – 37.

05062223341717263725171030062233062210271037132619272131221514281713282234171310

1. Arrange your data into an array.
2. Select your intervals. Explain your rationale for the intervals you selected.
3. Construct a frequency table. Remember, your frequency table should include class interval, frequency, relative frequency and cumulative relative frequency.
4. Construct a histogram based on your table. Hand-drawn histograms are fine–maybe preferable. Be sure to follow all of the steps in the module.
5. Construct a frequency polygon based on your table. Hand-drawn polygons are fine–maybe preferable. Be sure to follow all of the steps in the module.
6. Find the mean, median, and mode for the data.
7. Is the data in question 2 skewed? Why or why not?
8. Pretend you are emailing your friend about the “O” virus. What would you say?

SOLUTION

1. Array: 05, 06, 22, 23, 34, 17, 17, 26, 37, 25, 17, 10, 30, 06, 22, 33, 06, 22, 10, 27, 13, 26, 19, 27, 21, 31, 22, 15, 14, 28, 17, 13, 28, 22, 34, 17, 13, 10
2. Intervals: Rationale: To have equal intervals and have a better representation of the data, I would select the class intervals as 5-10, 10-15, 15-20, …, 35-40.
3. Frequency Table:

4. Histogram: (Diagram of histogram can be drawn here)
5. Frequency Polygon: (Diagram of frequency polygon can be drawn here)
6. Mean, Median, Mode: Mean: 22.2 Median: 22 Mode: 17
7. Skewness: The data is slightly skewed to the right as the mean is greater than the median.
8. Email to friend: Subject: O Virus Incubation Rates

Dear friend,

I wanted to share some information about the incubation rates of the mysterious “O” virus. The data has been recorded in days and ranges from 5 to 37. After analyzing the data, I found that the mean incubation time is 22.2 days, the median is 22 days, and the mode is 17 days. The data is slightly skewed to the right, which means that there are more values on the higher end of the incubation time.