Posted: February 4th, 2023
A very long charged conducting wire, of radius a = 12.0 cm, is enclosed by a concentric, conducting neutral hollow cylinder, as shown in the diagram above. The electric field is E⃗ 1�→1 = 1.60×104 N/C at b = 18.0 cm from the center of the wire and in the direction shown. What is the magnitude of the electric field at point P, a distance of c= 42.0 cm from the center of the wire?
SOLUTION
Gauss’s Law states that the total electric flux through any closed surface is proportional to the charge enclosed within the surface. Mathematically, it is expressed as:
Φ = Q/ε0
Where Φ is the electric flux, Q is the charge enclosed, and ε0 is the electric constant (also known as the vacuum permittivity). Gauss’s Law is one of the four Maxwell’s equations, which form the basis of classical electromagnetism.
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